Inserting a dielectric into a capacitor increases which property, at the same voltage?

Inserting a dielectric into a capacitor increases which property, at the same voltage?

• A. Capacitance
• B. Resistance
• C. Inductance
• D. Leakage current

Answer: (A)

Inserting a dielectric increases capacitance because capacitance measures how much charge the plates can hold per volt. The dielectric raises the permittivity between the plates, so C = εA/d with ε = ε0εr. Since εr > 1, C becomes larger while the plate area and separation stay the same. At the same voltage, the stored charge Q = CV increases accordingly, and the energy stored U = 1/2 CV^2 also goes up. The dielectric’s polarization lowers the internal field, but the key outcome for this question is the greater ability to store charge at the same voltage. Resistance and inductance aren’t increased by simply inserting a dielectric in this setup, and leakage current is not the primary effect here.

Inserting a dielectric increases capacitance because capacitance measures how much charge the plates can hold per volt. The dielectric raises the permittivity between the plates, so C = εA/d with ε = ε0εr. Since εr > 1, C becomes larger while the plate area and separation stay the same. At the same voltage, the stored charge Q = CV increases accordingly, and the energy stored U = 1/2 CV^2 also goes up. The dielectric’s polarization lowers the internal field, but the key outcome for this question is the greater ability to store charge at the same voltage. Resistance and inductance aren’t increased by simply inserting a dielectric in this setup, and leakage current is not the primary effect here.