In a transformer, if coil 1 has more turns than coil 2, then V1 is greater than V2.

In a transformer, if coil 1 has more turns than coil 2, then V1 is greater than V2.

• A. V1 is greater than V2
• B. V1 equals V2
• C. V1 is less than V2
• D. Cannot determine

Answer: (A)

The voltages in a transformer winding scale with the number of turns on that winding. In an ideal transformer, the ratio of voltages equals the ratio of turns: V1/V2 = N1/N2. If coil 1 has more turns than coil 2, then N1/N2 is greater than 1, so V1/V2 is greater than 1 and V1 is greater than V2. This is why a winding with more turns on the input side produces a higher voltage there and a lower voltage on the side with fewer turns—the device is stepping down the voltage when the primary has more turns. If the turns were equal, the voltages would be equal; if the turns were reversed, V1 would be less than V2.

The voltages in a transformer winding scale with the number of turns on that winding. In an ideal transformer, the ratio of voltages equals the ratio of turns: V1/V2 = N1/N2. If coil 1 has more turns than coil 2, then N1/N2 is greater than 1, so V1/V2 is greater than 1 and V1 is greater than V2. This is why a winding with more turns on the input side produces a higher voltage there and a lower voltage on the side with fewer turns—the device is stepping down the voltage when the primary has more turns. If the turns were equal, the voltages would be equal; if the turns were reversed, V1 would be less than V2.