If the product μ0 ε0 increases, what happens to the speed of light in vacuum?

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Multiple Choice

If the product μ0 ε0 increases, what happens to the speed of light in vacuum?

Explanation:
The speed of light in vacuum is determined by the electromagnetic properties of space, via c = 1/√(μ0 ε0). If the product μ0 ε0 increases, the value under the square root gets larger, making the denominator bigger and thus c smaller. Since μ0 and ε0 are positive real constants, the speed remains real and finite; it wouldn’t become imaginary. So the correct outcome is that the speed of light decreases.

The speed of light in vacuum is determined by the electromagnetic properties of space, via c = 1/√(μ0 ε0). If the product μ0 ε0 increases, the value under the square root gets larger, making the denominator bigger and thus c smaller. Since μ0 and ε0 are positive real constants, the speed remains real and finite; it wouldn’t become imaginary. So the correct outcome is that the speed of light decreases.

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