If the distance is doubled in the formula for gravitational force, how is the force affected?

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Multiple Choice

If the distance is doubled in the formula for gravitational force, how is the force affected?

Explanation:
Gravitational force follows an inverse-square law: F is proportional to 1 over the distance squared. So when the distance doubles, the distance squared becomes (2r)^2 = 4r^2. That makes the force drop to one fourth of its original value. Put simply, F' = F/4. For intuition, if the original force were 100 units at distance r, at twice that distance it would be 25 units. This is why the correct description is that the force becomes one quarter as strong.

Gravitational force follows an inverse-square law: F is proportional to 1 over the distance squared. So when the distance doubles, the distance squared becomes (2r)^2 = 4r^2. That makes the force drop to one fourth of its original value. Put simply, F' = F/4. For intuition, if the original force were 100 units at distance r, at twice that distance it would be 25 units. This is why the correct description is that the force becomes one quarter as strong.

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