If the distance between charges doubles, what happens to the force according to Coulomb's law?

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Multiple Choice

If the distance between charges doubles, what happens to the force according to Coulomb's law?

Explanation:
Coulomb’s law shows that the electrostatic force between two point charges is inversely proportional to the square of the distance between them: F ∝ 1/r^2. If the distance is doubled, r becomes 2r, and the force becomes F' ∝ 1/(2r)^2 = 1/(4r^2) = (1/4)F. So the force drops to one quarter of its original value, a reduction by a factor of four.

Coulomb’s law shows that the electrostatic force between two point charges is inversely proportional to the square of the distance between them: F ∝ 1/r^2. If the distance is doubled, r becomes 2r, and the force becomes F' ∝ 1/(2r)^2 = 1/(4r^2) = (1/4)F. So the force drops to one quarter of its original value, a reduction by a factor of four.

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